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11=5(x^2+1)+16
We move all terms to the left:
11-(5(x^2+1)+16)=0
We calculate terms in parentheses: -(5(x^2+1)+16), so:We get rid of parentheses
5(x^2+1)+16
We multiply parentheses
5x^2+5+16
We add all the numbers together, and all the variables
5x^2+21
Back to the equation:
-(5x^2+21)
-5x^2-21+11=0
We add all the numbers together, and all the variables
-5x^2-10=0
a = -5; b = 0; c = -10;
Δ = b2-4ac
Δ = 02-4·(-5)·(-10)
Δ = -200
Delta is less than zero, so there is no solution for the equation
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